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In this video we look +at the principle of decoding a message using the bifid cipher. We need decode some message using this cipher and the keyword. [We should] необходимо добавить, поскольку это единственное предложение в повелительном наклонении Make a Polybius square from letters (a rectangle 5x5 for English alphabet, where i and j are equivalent). In +the first row we put our keyword. +A Keyword has a the size of +the row. If +a keyword __has double same letters__ что-то не очень ясное we delete repeated again repeating letters. In residuary rows we write letter**s ** in alphabetical order excluding the letters <span style="color: #000080; font-family: 'Trebuchet MS',Helvetica,sans-serif; text-decoration: line-through;">contained in <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">of the keyword. <span style="color: #000080; font-family: 'Trebuchet MS',Helvetica,sans-serif;">Then under every letter of our ciphertext we write two numbers: the first <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">+one is the number of letter in the row <span style="color: #000080; font-family: 'Trebuchet MS',Helvetica,sans-serif; text-decoration: line-through;">of square ; the second <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">+one is the number of letter in the column. __The resulting sequence of numbers, divide into halves.__ <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">что здесь с синтаксисом? <span style="color: #000080; font-family: 'Trebuchet MS',Helvetica,sans-serif; text-decoration: line-through;">The second half we put <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">the second half under the first <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">+one. Then we space out numbers into digits. <span style="color: #000080; font-family: 'Trebuchet MS',Helvetica,sans-serif;"><span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">Опять неожиданно повелительное наклонение. Use our Polybius square. The first digit on <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">+the top is <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">+the number of <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">+the row in the square and the first digit from below is <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">+the number of <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">+the column. So, we get the first letter of decoded message. And the next digits on <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">+the top and from below are position<span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">s of letters in the square. So, we get <span style="color: #000080; font-family: 'Trebuchet MS',Helvetica,sans-serif; text-decoration: line-through;">remainder <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">remaining letters of decoded message. <span style="color: #000080; font-family: 'Trebuchet MS',Helvetica,sans-serif;">1330173599 <span style="color: #ff0000; font-family: 'Trebuchet MS',Helvetica,sans-serif;">4- но вообще-то за артикли надо двойку ставить.

We need to decode ciphertext, using bifid cipher with keyword. __At first, making the Polybius square.__ Э то какой-то обрывок без подлежащего и сказуемого. The Polybius square is the 5 by 5 __rate__. какое-то неверное слово. Put s our keyword in first row. Then in the remaining cells of matrix put s letters of the alphabet, besides letter «j» and letters, that +are in +the first row. Then we find two numbers of every letter of our ciphertext (the first number is the number in the row, the second number is the number in the column). As a result we obtain the sequence, which we have to split in half. We write the Second half of sequence we write under first half. Then we write make space between digits. We get a pairs of digits (one digit from the top, +a second digit from the bottom). The first digit is the row, the second digit is the column. Now we find the letters in matrix, using the __received__ parts of digits obtained. After that we get +a decoded message. 1330176556 4 - - как-то плоховато всё-таки

<span style="color: #800000; font-family: 'Comic Sans MS',cursive;">In this video we can learn decoding a message with the bifid cipher. <span style="color: #800000; font-family: 'Comic Sans MS',cursive;">So, we have encoded **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">+a ** message and the key word "eagles". At first**<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">, ** we should make a Polybius square - a rectangle 5x5. Location of each cells is discribed by two numbers: the raw number and the column number. And we write down the key word at the first row skipping over repeating letters. Then we fill the Polybius square <span style="color: #800000; font-family: 'Comic Sans MS',cursive; text-decoration: line-through;">by **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">with ** other letters __according to alphabet__. **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">in alphabetic order ** But there are 26 letters in <span style="color: #800000; font-family: 'Comic Sans MS',cursive; text-decoration: line-through;">ABC, **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">English ** and we have 25 cells. That's why we skip one letter ( the video author <span style="color: #800000; font-family: 'Comic Sans MS',cursive; text-decoration: line-through;">have **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">has!!!!! ** chosen **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">+the ** letter "J"). And there aren't **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">+any ** repeating letters! <span style="color: #800000; font-family: 'Comic Sans MS',cursive;">Now we write down the location of each letter of **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">+the ** encoded message (the __raw__ **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">row ** number,then the column number). Then we divide theese digits into two groups and write the second group under the first one (the numbers of digits in **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">+the ** 1st group and __in the second one are equal__). **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">что-то не то ** After that, we take one letter from the top and one letter from the bottom. This is the location of plaintext letter in Polybius square. Then we __search__ **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">почему? ** the second letter an**<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">d ** so on. <span style="color: #800000; font-family: 'Comic Sans MS',cursive;">So, we can decode **<span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive;">+a ** message with bifid cipher. <span style="color: #800000; font-family: 'Comic Sans MS',cursive;">user:Kurorisu


 * 4 **

<span style="color: #404040; font-family: Arial,sans-serif; font-size: 10pt;">This video shows us how to decrypt the ciphertext using the Polybius Square. <span style="font-family: Arial,sans-serif; font-size: 10pt;">We construct a 5*5 matrix __with the size 5*5__. After that, in the first row we have to write the keyword. +The Keyword must not be longer than 5 letters. In the other cells, we write <span class="hps" style="font-family: Arial,sans-serif; font-size: 10pt;">the alphabet. If the letter is used before, we don’t write it down( In addition, Besides, the symbol ‘I’ is equivalent to the symbol ‘j’). <span style="font-family: Arial,sans-serif; font-size: 10pt;">Now, e__ach character__ __ of __<span style="font-family: Arial,sans-serif; font-size: 10pt;"> __ciphertext we associate with +a two-digit number.__ T__he resulting sequence of numbers we need to split into two parts and write them under each other__. Thus, <span style="font-family: Arial,sans-serif; font-size: 10pt;"> we have two strings of letters. We consistently choose one character from each line, <span class="hps" style="font-family: Arial,sans-serif; font-size: 10pt;">and the resulting number __are looking for a match in the table__.э то я не понимаю: кто чего смотрит?! <span style="color: #404040; font-family: Arial,sans-serif; font-size: 10pt;">Thus, we obtain a sequence of letters - +the original message <span style="color: #000000; font-family: 'Comic Sans MS',cursive;">Tsykarev Aleksey В подчёркнутых предложениях обратный порядок слов.

4+ Лёша, всё забываю: по-английски сначала имя пишется, а потом фамилия.

Sorry, Oleg, you exceeded your time limit.

==== In this video we can learn decoding a message with the Bifid cipher. We need to decode the message “GHPK FNIG” using the Bifid cipher with the keyword “Eagles”. The first step we need to make a Polybius square. The Polybius square is the 5 by 5 grate. In the first row we write our keyword. Thus, each letter should be written only once. In residuary rows we write letters in alphabetical order, excluding the letters contained in the keyword. In addition, the letter 'I' and 'J' are the same. Then we get two numbers for each letter of our ciphertext, the first number is the number in the row, the second number is the number in the column. As a result we get a sequence of numbers that we need to divide in half. The second half we put under the first. Now we get the plaintext using the Polybius square, where the number of rows and columns We get a pairs of digits, one digit from the top, second digit from the bottom. ====